JSON.parse(String, TypeReference) 추가

master
mjkhan21 1 year ago
parent 84ad9e5366
commit 33f41fda83

@ -4,6 +4,7 @@ import java.io.InputStream;
import java.util.Set;
import com.fasterxml.jackson.core.JsonParser.Feature;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.DeserializationFeature;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.ObjectWriter;
@ -64,6 +65,14 @@ public class JSON extends AbstractComponent {
}
}
public <T> T parse(String json, TypeReference<T> typeRef) {
try {
return getObjectMapper().readValue(json, typeRef);
} catch (Exception e) {
throw runtimeException(e);
}
}
/**input .
* @param <T>
* @param input JSON input
@ -78,6 +87,14 @@ public class JSON extends AbstractComponent {
}
}
public <T> T parse(InputStream input, TypeReference<T> typeRef) {
try {
return getObjectMapper().readValue(input, typeRef);
} catch (Exception e) {
throw runtimeException(e);
}
}
/** JSON .
* @param obj
* @return JSON

@ -29,6 +29,7 @@ import java.util.function.Consumer;
import javax.net.ssl.SSLContext;
import cokr.xit.foundation.Assert;
import cokr.xit.foundation.Log;
import cokr.xit.foundation.data.JSON;
/** http .
@ -468,13 +469,15 @@ public class WebClient {
private String inJSON() {
Object body = bodyData();
String str = "";
if (!Assert.isEmpty(body))
return json().stringify(body);
str = json().stringify(body);
else if (!Assert.isEmpty(keyValues))
str = json().stringify(keyValues);
if (!Assert.isEmpty(keyValues))
return json().stringify(keyValues);
Log.get(getClass()).debug("json request:\n{}", str);
return "";
return str;
}
private String encode(String str) {

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