oftype(..) 수정

master
mjkhan21 4 months ago
parent e4a975d229
commit 75fd5da81b

@ -29,13 +29,13 @@ public class Descriptor extends AbstractComponent {
return new QName(!isEmpty(urn) ? "urn:" + urn : "", name); return new QName(!isEmpty(urn) ? "urn:" + urn : "", name);
} }
private static final List<String> types = List.of("string", "int", "long", "double"); private static final List<String> langTypes = List.of("string", "int", "long", "double", "boolean");
public QName oftype(String typeName) { public QName oftype(String typeName) {
String str = typeName.toLowerCase().replace("[]", ""); typeName = typeName.replace("[]", "");
return types.contains(str) ? return langTypes.contains(typeName.toLowerCase()) ?
new QName("http://www.w3.org/2001/XMLSchema", str) : new QName("http://www.w3.org/2001/XMLSchema", typeName) :
qname(typeName); qname(typeName);
} }

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